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LaMelo Ball remains in play for Cleveland in spite of Collin Sexton, Darius Garland’s presence

collin sexton, darius garland, lamelo ball

The Cleveland Cavaliers already have two promising young guards on the team in Collin Sexton and Darius Garland. However, it is rumored that LaMelo Ball remains in play for the Cavs whenever the 2020 NBA Draft takes place despite Sexton and Garland’s presence on the roster.

During an interview on 92.3 The Fan, Chris Fedor of Cleveland.com said Ball could end up on the Cavs if the front office in Cleveland gets its way, via Jacob Rude of Lonzo Wire:

“The sense that I get is that they have a top tier of guys and it’s three of them. It’s James Wiseman, Anthony Edwards and LaMelo Ball. And I think no matter what the Cavs do, they’re not going to let fit and position drive this decision. They’re going to take a bunch of different factors and they’re going cluster them together and weight them. But they’re not going to say ‘Because we drafted Darius Garland last year and Collin Sexton the year before, LaMelo Ball is out.’ They’re not going to do that. They don’t feel like they’re in a position to do that.”

Ball played 12 games in the NBL before suffering a foot injury. The youngest Ball brother averaged 17.0 points, 7.4 rebounds, and 6.8 assists per contest.

In the small-ball era, it would be intriguing to watch the Cavs throw out a lineup of Sexton, Garland, and LaMelo. The Cavs are going to have a high pick in the 2020 draft. They had the worst record in the Eastern Conference before the 2019-20 season was suspended due to COVID-19.

The Cavs are in desperate need of young talent at any position. Like Fedor says, the organization doesn’t have the luxury of being picky right now since they had the second-worst record in the NBA before games were suspended.

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